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0=x^2+10x-3000
We move all terms to the left:
0-(x^2+10x-3000)=0
We add all the numbers together, and all the variables
-(x^2+10x-3000)=0
We get rid of parentheses
-x^2-10x+3000=0
We add all the numbers together, and all the variables
-1x^2-10x+3000=0
a = -1; b = -10; c = +3000;
Δ = b2-4ac
Δ = -102-4·(-1)·3000
Δ = 12100
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{12100}=110$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-110}{2*-1}=\frac{-100}{-2} =+50 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+110}{2*-1}=\frac{120}{-2} =-60 $
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